We can use dereferenced integer pointers in integer expressions just
like any other integer variable. The type of a dereferenced integer
pointer is an integer.
The Program
/*********************************************
* File: express.c
* Author: S. Bogar
* Date: 12/31/98 11:55:00
* Section: 101
* SSN: 123-45-6789
* EMail: bogar@cs.umbc.edu
*
* A sample program that shows how to
* use pointers in an expression.
**********************************************/
#include <stdio.h>
int main ()
{
int i = 3, j = 5, *p, *q, *r ;
int result ;
p = &i ;
q = &j ;
if ( p == &i )
{
printf("p is pointing to i.\n") ;
}
/* Double dereferencing works */
result = **&p ;
printf("result = %d\n", result) ;
/* Dereferenced pointers are expressions */
result = 7 * *p / * q + 7 ;
printf("result = %d\n", result) ;
/* All these asterisks get confusing */
result = (* (r = & j) *= *p) ;
printf("result = %d\n", result) ;
return 0;
}
The Sample Run
p is pointing to i.
result = 3
result = 11
result = 15
Last Modified - Thursday, 17-Jan-2002 13:52:23 EST