;; Example algorithm to convert binary numbers to decimal
;; numbers.  Also works for hexadecimal or any other
;; base system, just by changing the value of the
;; variable "base"!

base = 2
sum = 0
pv = 1

;; "number" should be a list of binary (or base "base") digits
for each digit in number from last to first do {
    sum = sum + (digit * pv)
    pv = pv * base
}
return (sum)