The C do while loop

    do
    {
        ...statements...
    }while (condition);

the loop executes the ...statements... as long as condition / is true
...statements... is the "body"
not(condition) is the "termination condition"
since the condition is at the end, a do while loop always executes the "body" at least one time

Example problem Write a program to add a list of integers entered at the keyboard. The end of the input is indicated by entering 0 as a sentinel value. Program /***************************************** * File: dowhile.c * Author: D. Frey * Date: Fall 1999 * Section: 0101 * SSN: 123-45-6789 * E-Mail: frey@cs.umbc.edu * * This program adds a list of integers. The end of the * input is indicated by entering 0 as a sentinel value. * * This implementation uses a do while loop. *****************************************/ #include <stdio.h> int main() { int value, total; /* Give directions to user */ printf("This program adds a list of numbers.\n"); printf("Signal end of list with a 0.\n"); /* Initialize total */ total = 0; /* Get integers from the user until ** a 0 is entered */ do { printf("Enter an integer, 0 to end : "); scanf ("%d", &value); total += value; }while (value != 0); /* Print the total */ printf("The total is %d\n", total); return 0; } Output linux1[96] % a.out This program adds a list of numbers. Signal end of list with a 0. Enter an integer, 0 to end : 1 Enter an integer, 0 to end : 2 Enter an integer, 0 to end : 3 Enter an integer, 0 to end : 4 Enter an integer, 0 to end : 5 Enter an integer, 0 to end : 6 Enter an integer, 0 to end : 7 Enter an integer, 0 to end : 8 Enter an integer, 0 to end : 9 Enter an integer, 0 to end : 10 Enter an integer, 0 to end : 0 The total is 55 linux1[97] % CSEE | 201 | 201 S'03 | lectures | news | help Wednesday, 22-Jan-2003 12:59:28 EST